Apollonius <Pergaeus>, Apollonii Pergaei Conicorvm Lib. V. VI. VII. paraphraste Abalphato Asphahanensi : nunc primum editi ; additvs in calce Archimedis assvmptorvm liber, ex codibvs arabicis mss Abrahamus Ecchellensis Maronita latinos reddidit, Jo. Alfonsvs Borellvs curam in geometricis versione contulit & [et] notas vberiores in vniuersum opus adiecit

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160122Apollonij Pergæi C S V cum duplo trianguli F S V; ideſt quadratum I B æquale eſt duplo trian-
guli
I S C cum duplo trianguli F S V;
& quoniam propter parallelas C S, &
G
V, triangulum I C S ſimile eſt iſoſcelio, &
rectangulo triangulo I G V, erit,
quadratum
I C æquale duplo trianguli I C S iſoſcelei, &
rectanguli in C; ergo
exceſſus
quadrati I B ſupra quadratum I C æquale eſt duplo trianguli F S V;
eſt verò rectangulum, cuius baſis F S, altitudo verò C G æquale duplo trianguli
F
S V;
atque buiuſmodi rectangulum eſt exemplar applicatum ad abſciſſam G
C
, vt in notis prop.
16. 17. & 18. litera c. oſtenſum eſt igitur quadrati I B
exceßus
ſupra quadratum I C eſt exemplar applicatum ad abſciſſam G C:
Simili
153[Figure 153] modo quadratum I K oſtendetur æquale duplo trianguli I C S vna cum duplo
trapezij
L T S F;
atque dupli trianguli I C S cum duplo trianguli F S V ex-
ceſſus
ſupra duplum trianguli I C S cum duplo trapezij L T S F eſt duplum
trianguli
L T V;
ergo quadrati I B exceſſus ſupra quadratum I K eſt duplum
trianguli
L T V, ſeu exemplar applicatum ad G P differentiam abſciſſarum.
Poſtea quia triangula ſimilia E C F, E D M ſunt æqualia, cum eorum bomologa
latera
E C, E D æqualia ſint;
ergo addito communi triangulo I E V, erit trian-
gulum
E C F cum triangulo E I V, ſeu triangulũ I C S cum triangulo F S V
æquale
duobus triaugulis E D M, &
I E V, ſeu duobus triangulis M V N, &
N
I D:
erat autem quadratum I B æquale duplo trianguli I C S cum duplo tri-
anguli
F S V;
igitur quadratum I B æquale erit duplo trianguli M N V cum
duplo
trianguli N I D;
eſtque quadratum I D æquale duplo trianguli iſoſcelei,
rectanguli
I D N;
igitur quadratum I B ſuperat quadratum I D, eſtque exceſ-
ſus
duplum trianguli M N V ſeu exemplar applicatum ad G D.
Tandem quia
quadratum
I Q æquale eſt duplo trianguli iſoſcelei rectanguli I Q X, atque
quadratum
Q A æquale eſt duplo trapezij Q M;
igitur quadratũ bypotbenuſæ I
A
æquale eſt duplo trianguli I D N cum duplo trapezij X N M Z;
ergo exceſ-
ſus
quadrati I A ſupra quadratnm I D æqualis eſt duplo trapezij X N M Z;
exceſ-
ſus
autem trianguli N M V ſupra trapezium N Z eſt triangulum X Z V;
&
erat
quadrati I B exceſſus ſupra quadratum I D, triangulum ipſum M V N bis
ſumptum
.
Igitur quadrati I B exceſſus ſupra quadratum I A eſt duplum trian-
guli
X Z V, ſeu exemplar applicatum ad G Q.
Quod autem exemplaria æqualia
ſint
prædictis triangulis bis ſumptis, oſtenſum eſt in prop.
6. buius.

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